Im doing a unit test on math on edgenity math 8th unit test please i need help i have 2 hours to get it done The graph below displays the wrist circumferences and heights of six students in Alyssa’s classroom. A graph titled Wrist Circumference versus Height has wrist circumference (centimeters) on the x-axis and height (centimeters) on the y-axis. Points are at (13.8, 151), (14.2, 151), (15.2, 156), (15.6, 159), (16, 162) and (16, 165).

Is the height of these students a function of their wrist circumference?
Yes because as wrist circumference increases height also increases.
Yes because a line can be fit to these data to predict other pairings.
No because the height of 151 cm is paired with two wrist circumferences.
No because the wrist circumference of 16 cm is paired with two heights.

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation

a

step-by-step explanation:

the denominator cannot be the same as one of the factors.

8 denominator times 2 denominator = 16

and 7 numerator time 11 = 77

77/16= 77/16 ( they cannot be further simplified)

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)