For circle H, JN = x, NK = 2, LN = 3, and NM = 6. Solve for x. circle H with chords JK and LM intersecting at N inside the circle

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The value of x is 9 ⇒ C

Step-by-step explanation:

In a circle, if two chords intersected at a point inside it there are four segments created, two in each cord, the products of the lengths of the line segments on each chord are equal.

Let us use this rule to solve the question

In circle H

∵ Jk and LM are chords intersected at point N inside the circle

∴ The created segments are JN, Nk, and LN, NM

→ By using the rule above

∴ JN × NK = LN × NM

∵ JN = x and NK = 2

∵ LN = 3 and NM = 6

→ Substitute these values in the equation above

∴ x × 2 = 3 × 6

∴ 2x = 18

→ Divide both sides by 2 to find x

∴

∴ x = 9

∴ The value of x is 9

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,