Walking at a speed of 3 mph, Jack gets to school in 10 minutes and arrives at school right before the class starts. Today Jack needs to be at school 4 minutes earlier. How fast does Jack need to run this morning?

Jack needs to run at a speed of 1/12 mph

Step-by-step explanation:

Mathematically;

speed = distance/ time

Distance = speed * time

10 minutes = 10/60 h = 1/6 hours

The distance to the school will be

Distance = 3 * 1/6 = 1/2 = 0.5 miles

Now, he needs to be at school 4 minutes earlier, time will now be 10 - 4 = 6 minutes

To get the speed here;

Recall that the distance from above does not change

So speed = 0.5/6 mph 0r 1/12 mph

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.