For what values of m does the graph of y = 3x2 + 7x + m have two x-intercepts? m greater-than StartFraction 25 Over 3 EndFraction
m less-than StartFraction 25 Over 3 EndFraction
m less-than StartFraction 49 Over 12 EndFraction
m greater-than StartFraction 49 Over 12 EndFraction

m> 49/12

Step-by-step explanation:

The graph is a parabola . The Parabola with minimum point. So, Substitute the minimum value in the equation. Thus the graph of have two x-intercepts when.

The graph is a parabola with the minimum where x= -b/2a = -7/6.

To have 2 x intercepts, the value at the minimum point must be less than 0, i.e.

3(49/36) - 49/6 + m < 0

49/12 - 49/6 + m < 0

(49-98)/12 + m < 0

-49/12 + m < 0

m < 49/12

answer: the two figures are congruent.

step-by-step explanation: they're congruent because figure efgh is reflected across the x and y axis but it was also rotated.

hope it !

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2