The lifespans of zebras in a particular zoo are normally distributed. The average zebra lives 20.520.520.5 years; the standard deviation is 3.93.93.9 years. Use the empirical rule (68-95-99.7\%)(68−95−99.7%)(68-95-9 9.7%) to estimate the probability of a zebra living between 16.616.616.6 and 24.424.424.4 years.

n

step-by-step explanation:

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;