Please helpop Write an absolute value inequality that represents the situation. Then solve the inequality the difference between the areas of the figure is less than 2.

The absolute value inequality is_<2

The solution of inequality is_.

Absolute value inequality is |(2x + 12) - 12| < 2

Solution of the inequality is -1 < x < 1 (x = -1 or x = 1)

Step-by-step explanation:

Area of triangle = ½*base*height = ½*4*(x + 6) = 2(x + 6) = 2x + 12

Area of rectangle = length * width = 6*2 = 12

Given that the difference their areas is less than two, therefore, an absolute value inequality can be written as follows:

|(2x + 12) - 12| < 2

Find the solution by splitting the inequality into two:

(2x + 12) - 12 < 2 OR (2x + 12) - 12 > -2

Solve each

2x + 12 - 12 < 2

2x < 2

2x/2 < 2/2

x < 1

OR

2x + 12 - 12 > -2

2x > -2

2x/2 > -2/2

x > -1

Solution would be -1 < x < 1 (x = -1 or x = 1)

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2

step-by-step explanation: