Flaws occur at random along the length of a thin copper wire. The number of flaws per mm follows a Poisson Distribution with a mean of 2.3 flaws per mm. Determine the probability of exactly 2 flaws in 1 mm of wire.

0.265

Step-by-step explanation:

Given that :

Number of flaws per mm follows a poisson distribution:

Mean flaws per mm (x) = 2.3

Probability of exactly two flaws in 1 mm of wire

P(X = 2) = (x² * e^-x) / x!

P(x = 2) = (2.3² * e^-2.3) / 2!

P(x = 2) = (5.29 * 0.1002588) / 2

P(x = 2) = 0.265

hello i am doing good for you that it's summer in your country or state ; )

btw in my country we just have sun and rain as (because i live in the caribbean lol)

also, thx a lot for the points : )