A single 6-sided die is rolled twice. Find the probability of getting a 3 the first time and a 3 the second time. Express the probability as a simplified fraction.

1/36

Step-by-step explanation:

The event is mutually exclusive event. The occurrence of one foew not affect the other.

If a die is rolled once, the total outcome will be 6 since a die has 6 faces.

Probability = expected outcome/total outcome

If 3 is gotten when a die is rolled, the expected outcome will be 1.

Probability of getting a 3 will be 1/6

The probability of getting a3 the second time is also 1/6

The probability of getting a 3 the first time and a 3 the second time = 1/6×1/6 = 1/36

step-by-step explanation:

4227473658779875563886538705958641728563470543621287463824132573847969p05749365273847906970680574936214

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.