Use differentials (or equivalently, a linear approximation) to approximate sin(26∘) as follows: Let f(x)=sin(x) and find the equation of the tangent line to f(x) at a "nice" point near 26∘. Then use this to approximate sin(26∘).

they are simplified

step-by-step explanation:

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

the answer is 13/48

step-by-step explanation: