What is m∠2 + m∠3? Explain. Two lines and two line segments. Lines A B and C D are parallel horizontal lines with point C directly below point A and point D directly below point D. A vertical segment extends from A to C. A diagonal segment extends from C to B. Angle B A C is labeled 1. Angle A C B is labeled 3. Angle B C D is labeled 4. Angle A B C is labeled 2. A. 180; m∠1 + 90 = 180, so m∠2 + m∠3 = 180. B. 180; m∠1 + 90 = m∠2 + m∠3, so m∠2 + m∠3 = 180. C. 90; m∠1 + m∠2 + m∠3 = 180. m∠1 = 90, so m∠2 + m∠3 = 90. D. 90; ∠2 and ∠3 are corresponding angles, so m∠2 + m∠3 = 90.

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24