Question 4 (1 point) Phil Dunphy, a real estate agent, is considering whether he should list an unusual $345,584 house for sale. If he lists it, he will need to spend $5,892 in advertising, staging, and fresh cookies. The current owner has given Phil 6 months to sell the house. If he sells it, he will receive a commission of $19,166. If he is unable to sell the house, he will lose the listing and his expenses. Phil estimates the probability of selling this house in 6 months to be 33%. What is the expected profit on this listing? Your

Answers:

The expected profit on the listing is $2377.14

Step-by-step explanation:

Given that:

The probability of selling the house in 6 months is p = 0.33

The probability of not selling the house = 1 - 0.33 = 0.67

Suppose X represents the profit on the listing;

Then: we can compute the expected profit on the listing as:

E(X) = ($19166 × 0.33) - ($5892 × 0.67)

E(X) = $6324.78 - $3947.64

E(X) = $2377.14

Thus, the expected profit on the listing is $2377.14

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92