Please help me out. A square has an area of 90 square inches. Which two consecutive integers does a side length of the square fall between? The side length of a square with an area of 90 square inches falls between the integers
A and
B .

9 and 10

Step-by-step explanation:

Area of a square = s², where s = side length

Given that the square has an area of 90 in², the side length (s) of the square = √90.

Thus, 90 is not a perfect square and it's square root won't give us an integer.

Thus, √90 lies between two perfect squares namely, 81 and 100.

Therefore, the side length of the square would be:

√81 < √90 < √100

9 < √90 < 10.

The side length of the square lies between 9 and 10.

the given 6 = w/p is equivalent to 6p = w, where w is the total area of the walls and p is the area covered by a single can of paint.

knowing that 6 cans of paint will be needed, 6p = w becomes 6(6) = w = 36.   this tells us that the total area to be painted is 36 square units.