An elevator can carry 34 adults or 40 children at one time. During the course of a day, the elevator carries a full passenger load 53 times. If all the passengers were children, how many more people
would the elevator carry than if all the passengers were adults?
If all the passengers were children, the elevator would carry more passengers than if all the
passengers were adults.

The elevator carries 2120 children that day, if all those children were adults instead, the elevator would've carried 1802 adults that day. The question kind of confused me so I'm giving all I can.

9x

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240