On which interval is y = sin(x) strictly increasing? (Negative pi, negative StartFraction pi Over 2 EndFraction)

(0, pi)

(StartFraction pi Over 2 EndFraction, StartFraction 3 pi Over 2 EndFraction)

(0, StartFraction pi Over 2 EndFraction)

The function is strictly increasing on (0, π/2)

Step-by-step explanation:

We are given the function;

y = sin x

Let's find the derivative;

dy/dx = cos x

Now, Cos 0 = 1

Cos (π/4) = 1/√2

Cos (π/2) = 0

From the above, we can see that as x approaches 0 from (π/2), the value of (cos x) approaches 1. This means it's increasing from 0 to 1.

Thus, the function is strictly increasing on the interval (0, π/2)

1. 34

2. 268

3. x=14.4

step-by-step explanation: