the half life of c14 is 5730 years. Suppose that wood found at an archeological excavation site contains about 35% as much C14 as does living plant material. Determine when the wood was cut

The wood was cut approximately 8679 years ago.

Step-by-step explanation:

At first we assume that examination occured in 2020. The decay of radioactive isotopes are represented by the following ordinary differential equation:

(Eq. 1)

Where:

- First derivative of mass in time, measured in miligrams per year.

- Time constant, measured in years.

- Mass of the radioactive isotope, measured in miligrams.

Now we obtain the solution of this differential equation:

(Eq. 2)

Where:

- Initial mass of isotope, measured in miligrams.

- Time, measured in years.

And time is cleared within the equation:

Then, time constant can be found as a function of half-life:

(Eq. 3)

If we know that and , then:

The wood was cut approximately 8679 years ago.

answer is c

step-by-step explanation:

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.