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III
3.10 Unit Test: Relationships of Lines and Transversals - P
Given ZA and ZB are vertical angles with mZA = 10.2 + 5 and mZB = 152 - 10.
What is x?
Enter your answer in the box.
X =

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15