Find the general solution of the given higher-order differential equation. y''' + 3y'' + 3y' + y = 0

Step-by-step explanation:

We can determine the characteristic equation all we have to do is:

let y' = m, hence y" = m², y'" = m³

Therefore, the higher-order differential equation becomes:

m³ + 3m² + 3m + 1 = 0

(m + 1)(m² + 2m + 1) = 0

(m + 1)(m + 1)(m + 1) = 0

(m + 1)³ = 0

m = -1, -1, -1

Therefore the general solution is given as:

answer: i believe its b. if you sound out the sentences that sounds wrong.