A committee of 5 people is to be chosen from a group of 6 men and 4 women. How many committees are possible if: only men(3 Points)

There are six possible committees if only men are chosen

Step-by-step explanation:

Here, we want to find the number of possible committees if only men are chosen

In this case, what will happen is that we shall be selecting the 5 people from the available 6 men

Mathematically, we can have this in 6C5 ways

which is read as 6 combination 5 ways

And that will be 6 ways

So there are six possible committees if only men are selected

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

idk

step-by-step explanation: