If tan(x)=3/5 and sin(x)>0, what is sin(2x)?

With STEPS PLEASE AND NO TROLLING.

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sin2x =

Step-by-step explanation:

Given

tanx = =

This is a right triangle with legs 3 and 5

Let the hypotenuse be h , then using Pythagoras' identity

h² = 3² + 5² = 9 + 25 = 34 ( take the square root of both sides )

h =

Thus

sinx = =

cosx = =

Hence

sin2x = 2sinxcosx = 2 × × = =

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3