a bag contains 5 red balls and some Blue Balls if the probability of drawing a blue ball is double that of red ball find the number of a blue balls in the back

10

Step-by-step explanation:

Let the number of blue balls be x.

Number of red balls = 5

Total number of balls = x + 5

P (getting a red ball)  = 5/x+5

P (getting a blue ball)  = x/x+5

Given that

2(5/x+5) = x/x+5

10(x+5) = x^(2) +5x

x^(2)-5x-50=0

x(x-10)(x+5)

Now either x-10 = 0 or x+5= 0

But number of balls cannot be negative.

Hence, the number of blue balls is 10.

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)