A survey found that women's heights are normally distributed with mean 62.6 in. And standard deviation 2.5 in. The survey also found that men's heights are normally distributed with mean 68.3 in. And standard deviation 3.3 in. Most of the live characters employed at an amusement park have height requirements of a minimum of 57 in. And a maximum of 64 in. If the height requirements are changed to exclude only the tallest 50% of men and the shortest 5% of men, what are the new height requirements?

The new height requirements are minimum of 64.1875 inches and maximum of 68.3 inches

Step-by-step explanation:

To exclude the tallest 50% of men and shortest 5% of men, we need to find the critical z-value for a significance level of 0.5 & 0.05 and then solve for x in the z-score equation.

For significance value of 0.5, z = 0

We are given;

μ = 68.3 in

σ = 2.5 in

Thus from z = (x - μ)/σ, we have;

0 =(x - 68. 3)/2.5

0 = x - 68. 3

x = 68.3 inches for men max

Similarly, for significance value of 0.05, z = -1.645

Thus to find x;

-1.645 = (x - 68. 3)/2.5

-4.1125 = x - 68.3

x = 68.3 - 4.1125

x = 64.1875 inches for men min

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