Forty discrete math students are to be divided into eight discussion groups, each consisting of five students. In how many ways can this be done?

Step-by-step explanation:

Given data

the number of students n=40

the number of groups r= 8

We are going to use the combination approach to solve the problem

nCr= n!/r!(n-r)!

substituting into the expression for the number of ways we have

40C8= 40!/8!(40-8)!

nCr= 40!/8!(32)!

nCr= 40!/8!(32)!

nCr= 40*39*38*37*36*35*34*33*32!/8!(32)!

nCr= 40*39*38*37*36*35*34*33*/8!

nCr= 40*39*38*37*36*35*34*33*/8*7*6*5*4*3*2

nCr= 3100796899200/40320

nCr=76904685 ways

d

step-by-step explanation:

d

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !