Increases in snow levels are recorded with positive numbers. Decreases in snow levels are recorded with negative numbers. After a winter storm, the depth of the snow on Cherry Street was 10 \text{ cm}10 cm10, start text, space, c, m, end text. But then, the snow started melting at a rate of \dfrac{1}{3} \text{ cm} 3 1 cmstart fraction, 1, divided by, 3, end fraction, start text, space, c, m, end text per hour.

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Increases in snow levels are recorded with positive numbers. Decreases in snow levels are recorded with negative numbers. After a winter storm, the depth of the snow on Cherry Street was 10 cm. But then, the snow started melting at a rate of 1/3 per hour. What was the depth of the snow on Cherry Street after 3 hours?

9 cm

Step-by-step explanation:

The depth of snow = 10cm

Rate of melting = 1/3 cm per hour

1 hour = 1/3 cm

3 hours = x cm

Cross Multiply

= 3 hours × 1/3cm = 1 hour × x cm

x cm = 3 hours × 1/3cm/1 hour

x cm = 1 cm

Hence in 3 hours, 1 cm of snow would have melted.

Therefore, the depth of the snow on Cherry Street after 3 hours is

10cm - 1 cm

= 9 cm

step-by-step explanation:

12475909

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.