Consider the function and its inverse. and

When comparing the functions using the equations, which conclusion can be made?

f(x) = x^2 +4 and f^-1 (x) = square root of x-4

The domain of f(x) is restricted to x ≥ 0, and the domain of f–1(x) is restricted to x ≥ 0.

The domain of f(x) is restricted to x ≥ 0, and the domain of f–1(x) is restricted to x ≤ 0.

The domain of f(x) is restricted to x ≤ 0, and the domain of f–1(x) is restricted to x ≥ 4.

The domain of f(x) is restricted to x ≤ 0, and the domain of f–1(x) is restricted to x ≤ 4.

The domain of is restricted to , and the domain of is restricted to .

Step-by-step explanation:

From Function Theory we know that domain of a function is the set of values such that an image exist. Let and the function and its inverse, respectively.

At first glance we notice that function is a second order polynomial and every polinomial is a continuous function and therefore, there exists an image for every element of domain.

But domain of its inverse is restricted to every value of x so that , which means that .

Finally, we concluded that following answer offers the best approximation to our result:

The domain of is restricted to , and the domain of is restricted to .

4x and 6y

im not sure though