This setup is used in the previous problem. Suppose a Markov chain has three states, A, B, and C. From state A, the process changes randomly to a different state. From state B, the process is equally likely to stay as to change. If it changes, each other state is equally likely. From state C, the process is three times as likely to change as to stay, but it never changes to B. Find the proportion of time this process spends at each state in the long run. Enter these probabilities below, in order. Give exact answers (use fractions if necessary).

answer: ok

step-by-step explanation:

6.9

step-by-step explanation:

simple math really

6 1/2 times 0.6 = 3.9

but if you are just doing 6 and not 6 1/2 then the answer is 3.6

6, 10

9, -13

12, -21

18, -23

step-by-step explanation:

you just add 6 to the x-coordinate and subtract 10 from the y-coordinate.

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !