In the game of roulette, a player can place a $ bet on the number and have a probability of winning. If the metal ball lands on , the player gets to keep the $ paid to play the game and the player is awarded an additional $. Otherwise, the player is awarded nothing and the casino takes the player's $. What is the expected value of the game to the player? If you played the game 1000 times, how much would you expect to lose?

Complete Question

The complete question is shown on the first uploaded image

a

The expected amount to be lost is  0.5263 cents per game

b

The expected amount to be lost is  

Step-by-step explanation:

From the question we are told that

   The probability of winning is  

Generally the probability of losing is mathematically evaluated as

=>        

=>        

Generally the expected value is mathematically represented as

Here is a discrete variable (i.e it is a countable )  are outcomes of the player winning and the player losing

So

Now the outcome of winning is  making $350  so

        the outcome of losing is losing $10  so  

So

hence the expected amount to be lost is  0.5263 cents per game

If you played the game 1000 times, the amount that is expected to be lost is  

=>

Hence the expected amount to be lost is  

48 / 6 = x

in this case, x will equal the amount of money in each card!

x therefore will be 8.

trent had $8 in each birthday card.

answer: bea's uncle is 25 years old.

step-by-step explanation:

given the equation , we can say that the variable "x" represents the age of bea's uncle. then to find his age, we need to solve for "x":

we must add 15 to both sides of the equation:

now we need to divide both sides of the equation by 3:

therefore, we can conclude that bea's uncle is 25 years old.