If you draw three cards from a regular deck of 52 cards, keeping each card out of the deck after you draw it, what are the chances you draw a seven and two queens?

There are four 7's in a standard card. Chance of getting a 7 first is 4/52 = 1/13
There are four queens in a standard card. Chance of getting a queen in the second drawing is 4/51 and chance of getting a queen in the third drawing is 3/50.

Therefore, chance of drawing a seven and two queens is 1/13 x 4/51 x 3/50 = 2/5525

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!