What is the length of the line segment with endpoints (−3, 8) and (7, 8) ?

length/distance = 10 units

Step-by-step explanation:

Use the distance formula for both points / length / magnitude, d = √((x2-x1)^2+(y2-y1)^2).

Given endpoints (-3,8) [(x1,y1)], and (7,8) [(x2,y2)], plug in the corresponding y, and x values of both coordinates, and simplify.

√((8-8)^2+(7-(-3))^2) = √(0^2+10^2) = √100 = 10

*This may be in units if the unit used is unspecified.*

Also since the y values of both coordinates are the same, you can just subtract the x values in the coordinates, and take the absolute value since distance/length cannot be negative.

statement #3: proof- ang is congruent to ang ecd : angles are congruent.  

step-by-step explanation:

1: the missing angles in statement #3  

a.) acb  

reason- the reason why the answer is acb is because angle ecd and angle acb are both the same size *that's what the word congruent means this is really simple.  

2: the missing word in reason #3  

c.) vertical  

reason- the reason why the answer is vertical is because the angles in that diagram on figure 2 is slanted, which is vertical, and the e and a both lay on vertical lines. along with the other's, but e and a are the 2 main points you want to focus on. and c is kind of like your starting point, because c is for both angles, not just one.  

i hope that was and understanding.