A 4-digit number contains at least one even digit. How many such numbers are there? Please help me. I will mark brainliest

Given:

A 4-digit number contains at least one even digit.

To find:

How many such numbers are there?

Solution:

Digits are 0,1,2,3,4,5,6,7,8,9.

Number of odd digits = 5

Number of even digits = 5

4-digit numbers are from 1000 to 9999.

Total number of 4-digit numbers = 9000

Possible ways to get odd digits on all the 4 places is

It means 625 numbers are their in which all 4 digits are odd.

To find total 4-digit number that contains at least one even digit, subtract the numbers which contains only odd numbers from the total 4-digit numbers.

Therefore, total 4-digit number that contains at least one even digit is 8375.

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