Solve the following problem. Be sure to show all the steps (V. E.S. T.) and work in order to receive full credit. The sum of three numbers is 26. The second number is twice the first and the third number is 6 more than the second. Find the numbers.

   x+2x+(2x+6)=26

                 x+2x+2x= 26-6

                5x=20

                x=20/5

                x=4

                First number=x=4

                Second number=2x=2(4)=8

                Third number=2x+6=2(4)+6=8+6=14

Step-by-step explanation:

Hope it help. Sorry if its wrong i looked it up and got the answer from some other dude. If u need sum else lmk

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents