A train leaves the station at 6:00 P. M. traveling west at 80 miles per hour. On the parallel track, a second train leaves the station 3 hours later traveling west at 100 miles per hour. At what time will the second train catch up with the first train? SHOW YOUR WORK PLZ I WILL GIVE YOU BRINLEY
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9 AM

Step-by-step explanation:

Let t = traveling time of the 1st train, when the 2nd train catches up

Then

(t-3) = traveling time of the the 2nd train.

When this occurs, both trains will have traveled the same distance;

Write a distance equation: Dist. = speed * time

100(t-3) = 80t

100t - 300 = 8t

100t- 80t = +300

20t = 300

t = 300/20

t = 15 hrs.

Time = 6 PM + 15 hrs. = 9 AM the next day

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step-by-step explanation:

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