Find two posiitive even consecutive integers such that the square of the smaller integer is 10 more than the larger integer.

The two numbers are 4 and 6

Step-by-step explanation:

Suppose we have:

x=The smallest even integer

x+2=Next even integer

Recall even numbers occur every other integer.

The condition of the problem states the square of the smaller integer is 10 more than the longer integer:

Rearranging and simplifying:

Factoring:

We have two solutions:

x=4, x=-3

Since the integers must be positive:

x=4

Next even integer= x+2=6

The two numbers are 4 and 6

54liters ueafhkibeisbf

erica would now have 20 bottles of water because 26-6=20.

i hope this : )