If p(x)=(3x+2)(2x−3), what are the zeros of the polynomial? x=-23 and x=32

x=23 and x=-32

x=-2 and x=3

x=2 and x=-3

Option A is the correct answer. ; x=-2/3 and x=3/2

Step-by-step explanation:

We have been given that p(x)=(3x+2)(2x−3) is a polynomial.

According to the question's statement, Question asks us to find the zeros of the polynomial.

Let's head to the question in order to get required answer.

p(x)=(3x+2)(2x−3)

=> p(x) = 3x(2x-3) + 2(2x-3)

=> p(x) = 6x² - 9x + 4x - 6

=> p(x) = 6x² - 5x - 6 (This is the standard form for the given polynomial)

Now, We need to find the zeros of the polynomial. So, In order to find its zeros, we need to put p(x).

p(x) = (3x+2)(2x-3)

=> 0 = (3x+2)(2x-3)

=> (3x+2) = 0 or (2x-3) = 0

=> x= -2/3 or x = 3/2

Hence, If p(x)=(3x+2)(2x−3), x = -2/3 & x= 3/2 are the zeros of the polynomial.

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl