Triangle A B C. Angle C is 90 degrees. Hypotenuse A B is 13, adjacent B C is 5, opposite A C is 12. For the triangle above, find sin B.
a.
25°
c.
0.923
b.
0.385
d.
18°

sin = opp/hyp

sin B = 12/13

sin B = 0.923

C

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

what is the original number? you forgot to add it.