Suppose J is between H and K. Use the Segment Addition Postulate to solve for x. Then find the length of each segment. If HJ=x+10 JK=9x KH=14x−58 a) Draw a sketch of the segments described above b) Write an equaation using the segment addition postulate that will help you solve the problem ___+ ___= c) combine like terms ( x terms on one side of the equal sign and numbers in the other side of the equal sign) = d) x= __ HJ= __ JK= __ HK= __

x= 17

HJ= 27

JK= 153

HK= 180

Step-by-step explanation:

If HJ=x+10

JK=9x

KH=14x−58

a) The diagram of sketch of the segments described above is attached to this answer.

b) KH = HJ + JK

14x - 58 = (x + 10) + 9x

14x - 58 = x + 10 + 9x

c)

14x - 58 = x + 10 + 9x

14x - 58 = 10x + 10

Collect like terms

14x - 10x = 10 + 58

4x = 68

Divide both sides by 4

4x/4 = 68/4

x = 17

d)

x= 17

HJ= x + 10

= 17 + 10

= 27

Hence, HJ = 27

JK= 9x

= 9 × 17

= 153

Hence, JK = 153

HK=14x −58

HK = 14 × 17 - 58

= 238 - 58

= 180

Hence, HK = 180

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

21

jk it's 20

step-by-step explanation: