Pete's dad usually deposits $25 into his bank account every week. for the next 8 weeks , he wants to deposit more than the usual $25, and he wants the extra amount deposited to be the same each week. which inequality and solution show how much more he can deposit each week and keep the total of his deposit above 500 for those 8 weeks? 8(25+x)> 500; x> $300
25+8x> 500; x> $59.37
8(25+x)> 500; x> 37.50
8(25)+x> 500; x> $300

Step-by-step explanation:

Given : For the next 8 weeks , he wants to deposit more than the usual $25.

To Find: He wants the extra amount deposited to be the same each week. which inequality and solution show how much more he can deposit each week and keep the total of his deposit above 500 for those 8 weeks.

Solution:

His usual deposit = $25

He wants the extra amount deposited to be the same each week.

Let x be the extra amount.

So, Amount need to be deposited per week = 25+x

Amount need to be deposited 8 weeks = 8(25+x)

Now we are given that he total of his deposit should be above 500.

So,

So, inequality :

Solution:  

Thus Option C is correct.

Hence , the inequality and solution which shows how much more he can deposit each week and keep the total of his deposit above 500 for those 8 weeks is

no he doesnt because "-16' is negatiive

step-by-step explanation:

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.