P1=(-1,3) and P2=(5,-1)

Find the distance from p1 to P2

7.21

Step-by-step explanation:

Given that:

P1=(-1,3) and P2=(5,-1)

Distance between two points :

d = Sqrt[(x2 - x1)² + (y2 - y1)²]

x1 = - 1 ; y1 = 3

x2 = 5 ; y2 = - 1

d = Sqrt[(5 - (-1))² + ((-1) - 3)²]

d = Sqrt[(5 + 1)² + (-1 - 3)²]

d = sqrt[(6)^2 + (-4)^2]

d = sqrt(36 + 16)

d = sqrt(52)

d = 7.21

b mark me branliest thx

step-by-step explanation:

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube