Calculate the mean and the standard deviation of the sampling distribution of possible sample proportions for each combination of sample size (n) and population proportion (p).

Here is the full question.

Calculate the mean and the standard deviation of the sampling distribution of possible sample proportions for each combination of sample size (n) and population proportion (p).

a.) n = 64, p = 0.8

b.) n = 256, p = 0.8

a.) Mean = 0.8

   Standard deviation = 0.05

b.)  Mean = 0.8

     Standard deviation = 0.025

Step-by-step explanation:

From the given information:

a.)

The population parameter (p) is the mean of the sampling distribution for the sample proportion.

Thus; The  Mean = 0.8

The standard deviation of the  distribution can be calculated as follows:

Let's first represent the standard deviation with Sd()

Then:

where;

p = 0.8

n = 64

Then:

b.)

The population parameter (p) is the mean of the sampling distribution for the sample proportion.

Thus; The  Mean = 0.8

The standard deviation of the  distribution can be calculated as follows:

Let's first represent the standard deviation with Sd()

Then:

where;

p = 0.8

n = 256

Then:

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.

answer is 33

step-by-step explanation: