Using the Pythagorean Theorem What is the length of side a when b=24 and
c=262

261

Step-by-step explanation:

a²+b² = c²

Given, a = ?

b = 24

c = 262

a² = c² - b²

a²= 262² - 24²

a² = 68644 - 576

a² = 68068

a = √68068

∴ a=  260.89844

can be said as 261

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)