Mathematics, 22.10.2020 23:01 nstacie40
An object is launched at 19.6 meters per second (m/s) from a 58.8-meter tall platform. The equation for the object's height s at time t seconds after launch is s(t) = –4.9t2 + 19.6t + 58.8, where s is in meters. At what height will the object be after 3 seconds?
Answers: 3
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An object is launched at 19.6 meters per second (m/s) from a 58.8-meter tall platform. The equation...
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