A car has an initial velocity of 10 m/s and final velocity of 43 m/s. The time taken to reach the final velocity was 3 seconds. What is the acceleration of the car?
Hint: Acceleration (in terms of velocity) = (final velocity - initial velocity)/(time) *

160 m/s

Step-by-step explanation:

vi= 10m/s

a= 5om/s*2

t=3 second

vf=?

frist step: find s(distance)

s=vit+1/2 at*2=10m/s x3s +0.5 x50m/s*2 (3s)*2 =30m+225m=255m

second : find vf

s=(vf+vi)/2 xt

vf=2s/t- vi=2(255m)/3s -10 m/s=170 m/s-10m/s=160m/s

Therefore , the final velocity of the car is 160m/s

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i