The price of Stock A at 9 A. M. Was $14.17. Since then, the price has been increasing at the rate of $0.11 each hour. At noon the price of Stock B was $14.67. It begins to decrease at the rate of $0.16 each hour. If the two rates continue, in how many hours will the prices of the two stocks be the same?

0.63 hours

Step-by-step explanation:

We are told that at 9am, the price of Stock A was $14.17 and we are told it increases by $0.11 each hour.

Thus, for x hours, the price will be;

P_a = 14.17 + 0.11x

Now,by noon, it would have been 3 hours.

Thus;

P_a = 14.17 + 0.11(3)

P_a = 14.17 + 0.33

P_a = $14.50

Now, at that same noon, another product known as stock B had a price of $14.67. We are told it begins to decrease at the rate of $0.16 each hour.

Now, we want to find how many how many hours will the prices of the two stocks be the same. If the number of hours is x, this means that;.

14.5 + 0.11x = 14.67 - 0.16x

Rearranging,we have;

0.11x + 0.16x = 14.67 - 14.5

0.27x = 0.17

x = 0.17/0.27

x = 0.63 hours

y=mx+b

step-by-step explanation:

m is slope, b is y-intercept