The braking distance of a car can be modeled by d=s+(s^2/10) where d is the distance (in feet) that the car travels before coming to a stop, and s is the speed at which the car is traveling (miles per hour). Find the speed that results in a braking distance of 90 feet.

s=25.41mph

Step-by-step explanation:

In order to solve this problem, we must start by setting the given equation equal to the 90 feet you have available to stop the car, so the equation will then look like this:

we can then move everything to the left side of the equation so we get:

we can now multipy both sides of the equation by 10 so we get:

Next, we can solve this equation by using the quadratic formula, so we get:

and then we input the values:

and solve:

this gives us two answers:

s=-35.41mph

s=25.41mph

we pick the first answer since we will assume the disceleration goes in the negative direction, so we get:

s=25.41mph

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3

1/8 3/16 3/4

step-by-step explanation:

you put them as all the same denominator and multiply