Joe has 2 solutions that contain alcohol and is mixing them with each other he uses 500 milliliters less of solution A than solution B Solution A is 14% alcohol and solution B is 19% alcohol how many milliliters of solution B does he use if the resulting mixture has 161 milliliters of pure alcohol

700 milliliters of solution B

Step-by-step explanation:

Joe has 2 solutions that contain alcohol and is mixing them with each other he uses 500 milliliters less of solution A than solution B

A = B - 500

Solution A is 14% alcohol and solution B is 19% alcohol

14%A +19%B = 161 mm

0.14A + 0.19B = 161

Substitute for B - 500 for A in the equation below:

0.14A + 0.19B = 161

0.14(B - 500) + 0.19B = 161

0.14B - 70 + 0.19B = 161

Collect like terms

0.14B + 0.19B = 161 + 70

0.33B = 231

B = 231/0.33

700 milliliters

A = B - 500

A = 700 - 500

A = 200 milliliters

Therefore, he uses 700 milliliters of solution B

answer is c

step-by-step explanation:

answer:

payment just for service  

→

$

87.12

payment for service including tax

→

$

94.09

explanation:

service only with 20% tip  

→

$

72.6

(

1

+

20

100

)

=

$

87.12

in the opening of the question the word 'service' is associated only with the pretax value.

the closing part of the question asks: how much did she pay for the  

service

−−−−−−  

so technically the answer is  

→

$

72.6

(

1

+

20

100

)

=

$

87.12

however, the intention of the question provider may have been that your answer is to be  

$

87.12

(

1

+

8

100

)

=

$

94.09

to 2 decimal places.

'

payment just for service  

→

$

87.12

payment for service including tax

→

$

94.09

tony b

mar 21, 2017

answer:

trying to explain it another way

explanation:

service charge  

.

→

$

72.60

20% tip  

20

100

×

$

72.60

=

$

14.52

−−−−−−  

←

add

$

87.12

tax  

8

100

×

$

87.12

=

$

6.97

−−−−−  

←

add

$

94.09

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