Fernando and Damon are playwrights. A literary critic notices that the two playwrights have written the same number of acts during their careers, even though all of Fernando's plays have 9 acts and all of Damon's plays have 3 acts. What is the smallest number of acts each must have written?

9

Step-by-step explanation:

Given: All of Fernando's plays have 9 acts and all of Damon's plays have 3 acts.

The smallest number of acts each must have written = Least common multiple of 9 and 3

Since 9= 3 x 3

3 = 3 x 1

LCM(3,9) = 3 x 3 = 9

Hence, the  smallest number of acts each must have written = 9

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

where's the diagram?

step-by-step explanation: