In quadrilateral ABCD shown below it is known that BC is perpendicular CD, angle A=5x+12, and angle C=7x-36. Given this information, which of the following is the degree measure of angle A?

m∠A = 102°

Step-by-step explanation:

In quadrilateral ABCD, BC is perpendicular to CD

m∠BCD = 90°

(7x - 36) = 90°

7x = 90 + 36

7x = 126

x = 18

Since, m∠A = (5x + 12)

Therefore, m∠A = (5×18) + 12

                           = 90 + 12

                           = 102°

Measure of angle A = 102°

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation: