Express the product of 2.2 mm and 6.00 mm using the correct number of significant digits.

The product would be 13.

Step-by-step explanation:

Since we have given that

2.2 mm and 6.00 mm

We need to find the product of these two numbers using number of significant digits.

Product of above two numbers be

Using the correct number of significant digits, it would be

13 mm².

Hence, the product would be 13.

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb