A plane is flying at 1000 meters above the ground and fires a laser 60 degrees of of straight down. what is the distance the light traveled to the ground?

Step-by-step explanation:

The distance the light traveled to the ground is the range of the plane expressed as:

R = U*√2H/g

U is he velocity

H is the max height

g is the acc. due to gravity

Let us get U first using the formula

H = u²sin²Ф/2g

1000 = u²sin²60/2(9.81)

1000*19.62 = 0.8660u²

19620 = 0.8660u²

u² = 19620/0.8660

u² = 22655.88

u = √22655.88

u = 150.52m/s

Next is to get the range

R = 150.52√2(1000)/9.81

R = 150.52 √2000/9.81

R = 150.52√203.87

R = 150.52*14.28

R = 2149.16m

Hence the distance the light traveled to the ground is 2,149.16m

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step-by-step explanation:

answer: a.

step-by-step explanation: the answer is a. because, you need to converge the fractions to find a solution.