The following is an incorrect flowchart proving that point L, lying on line LM which is a perpendicular bisector of segment JK , is equidistant from points J and K: Segment JK intersects line LM at point N

Line LM is a perpendicular bisector of segment JK, Given. Two arrows are drawn from this statement to the following two stateme

What is the error in this flowchart? (5 points)

JL and KL are equal in length, according to the definition of a midpoint.

An arrow is missing between ∠LNK = 90° and ∠LNJ = 90° and ∠LNK ≅ ∠LNJ.

An arrow is missing between the given statement and ∠LNK ≅ ∠LNJ.

Triangles JNL and KNL are congruent by the Angle-Angle Side (AAS) Postulate.

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step-by-step explanation:

dude thats to long figure it

step-by-step explanation:

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.