The larger of two numbers is one more than four times the smaller number. If the sum of the numbers is 106, find the numbers

Here's what we know:

x + y = 106 (their total is 106)

x = 4y + 1 (the larger is 4-times the smaller plus one)

From here we have a substitution method--we have a value for x to plug in:

(4y + 1) + y = 106

Simplify:

5y + 1 = 106

Subtract 1 from both sides:

5y = 105

Divide both sides by 5:

y = 21

Now that we know y, we can solve for x:

x = 4 * 21 + 1

x = 84 + 1

x = 85

Now to check our

85 + 21 = 106

106 = 106

Step-by-step explanation: this should be right

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐